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JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

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Application +4 | -1
If OO is the origin and the coordinates of AA and BB are (x1,y1)\left(x_1, y_1\right) and (x2,y2)\left(x_2, y_2\right) respectively then OA×OBcos⁡∠AOBO A \times O B \cos \angle A O B is equal to
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Correct option: B
x1x2+y1y2x_1 x_2+y_1 y_2
Option B (x1x2+y1y2x_1 x_2+y_1 y_2) is correct because it represents the dot product of the vectors OA and OB, which is equal to |OA||OB|cos(∠AOB).

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