NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Hard

1 of 1

Application +4 | -1

An ideal gas undergoes isothermal expansion from

(10 \mathrm{~atm}, 1 \mathrm{~L})

(1 \mathrm{~atm}, 10 \mathrm{~L})

either by path-I (infinite stage expansion) or by path-II (first against

5 \mathrm{~atm}

and then against

1 \mathrm{~atm}).

The value of

\left(\frac{q_{\text {path-I}}}{q_{\text {path-II}}}\right)

View answer and explanation

Correct option: A

\frac{2.303}{1.3}

Option A (

\frac{{2.303}}{{1.3}}

) is correct because it represents the ratio of heat absorbed in an infinite stage expansion to that in a two-stage expansion, calculated using the isothermal work formula.

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →

The internal energy of one mole of a gas is: An ideal gas is allowed to expand both reversibly and irreversibly in an isolated system. If

{T_i}

is the initial temperature and

{T_f}

is the final temperature, which of the following statements is correct? For which of the process, ∆S is negative? The work done by a weightless piston in causing an expansion ∆V (at constant temperature), when the opposing pressure, P is variable, is given by: Assertion :- At constant pressure of the change

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

work done is negative.

Reason :- During phase transition work done is always negative. For the reaction,

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

. Hence,

\Delta G