NEET UG CHEMISTRY MCQ: REDOX REACTIONS

1 Hard

1 of 1

Analyzing +4 | -1

In the reaction,

2 \mathrm{Cu}_2 \mathrm{O}+\mathrm{Cu}_2 \mathrm{~S} \longrightarrow 6 \mathrm{Cu}+\mathrm{SO}_2

, sulphur of

\mathrm{Cu}_2 \mathrm{~S}

helps copper both in

\mathrm{Cu}_2 \mathrm{~S}

itself and

\mathrm{Cu}_2 \mathrm{O}

to decrease its oxidation number, therefore sulphur of

\mathrm{Cu}_2 \mathrm{~S}

View answer and explanation

Correct option: B

reductant

Option B (reductant) is correct because the sulphur in Cu2S causes a decrease in the oxidation number of copper, thus acting as a reducing agent.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }