JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

In a

\triangle A B C

, the sides

a, b

and

c

are in AP.Then,

\left(\tan \frac{A}{2}+\tan \frac{C}{2}\right): \cot \frac{B}{2}

is equal to

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the calculated ratio is 2/3, which is not among the given options.

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{p_1},{p_2},{p_3}

\Delta \;ABC

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\Delta

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5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

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\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s