JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1

In a

\Delta \,ABC,\,\;B = \frac{\pi }{8}

and

C = \frac{{5\;\pi }}{8}

. The altitude from

A

to the side

BC

, is

View answer and explanation

Correct option: A

\frac{a}{2}

Option A (

\frac{a}{2}

) is correct because using the sine rule and area of triangle formula, the altitude from A to BC is found to be

\frac{a}{2}

More Questions from PROPERTIES OF TRIANGLES

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{p_1},{p_2},{p_3}

\Delta \;ABC

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\Delta

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k

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a = \left( {b - c} \right)\sec \theta

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\Delta

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\tan A

A

2 s