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JEE PHYSICS MCQ: GRAVITATION

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Find the sum of given series

F=GMmr2[1+12+14+…∞∣ ]F=\frac{G M m}{r^2}\left[\left.1+\frac{1}{2}+\frac{1}{4}+\ldots \infty \right\rvert\,\right]
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Correct option: A
F=2GMmr2F=\frac{2 G M m}{r^2}
Option A is correct because the given series is a geometric progression with a sum to infinity of 2, resulting in the force being 2GMm/r².

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