JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \frac{\left(\tan ^{-1} x\right)^3}{1+x^2} d x

is equal to

View answer and explanation

Correct option: B

\frac{\left(\tan ^{-1} x\right)^4}{4}+C

Option B is correct because the integral simplifies to (tan^(-1)(x))⁴ / 4 + C after recognizing the derivative of tan^(-1)(x).

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