Skip to main content
Back to SYSTEM OF CIRCLES

JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

1 Easy
1 of 1
Application +4 | -1
The point from which the tangents to the circles

x2+y2−8x+40=0x^2+y^2-8 x+40=0

5x2+5y2−25x+80=05 x^2+5 y^2-25 x+80=0

x2+y2−8x+16y+160=0x^2+y^2-8 x+16 y+160=0

are equal in length, is
View answer and explanation
Correct option: C
(8,−15/2)(8,-15 / 2)
Option C ((8,−15/2)(8,-15 / 2)) is correct because it represents the radical center of the three circles, where the lengths of tangents from that point to each circle are equal.

More Questions from SYSTEM OF CIRCLES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.