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JEE PHYSICS MCQ: THERMODYNAMICS

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When a mole of an ideal gas expands isothermally at 27∘C27^\circ C to double its original volume, the work done by the gas is [R=8.314   deg⁡−1 mol−1][log⁡102=0.3010]\left[ {R = 8.314\,\,\,{{\deg }^{ - 1}}\,{\text{mo}}{{\text{l}}^{ - 1}}} \right]\left[ {\log _{10}^2 = 0.3010} \right]
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Correct option: C
1726 J
Option C (1726 J) is correct because it is the work done calculated using the isothermal expansion formula with the given values.

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The work done in which of the following process is zero? Water is used to cool the radiators of engines in cars because A gas expand 0.25  m30.25\,\,{m^3} at constant pressure 103N/m2,{10^3}N/{m^2}, the work done is A thermodynamic process in which temperature TT of the system remains constant though other variable PP and VV may change, is called What is the slope for an isothermal process? For adiabatic processes (γ=CpCv)\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)
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