For a reaction, $A\left( l \right) \to 4B\left( g \right)$ if $\Delta U = 4.5\,kJ$ and $\Delta S = 60\,J{K^{ - 1}}$ at ${27^0}C$ then $\Delta G$ will be

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Application +4 | -1

For a reaction,

A\left( l \right) \to 4B\left( g \right)

\Delta U = 4.5\,kJ

and

\Delta S = 60\,J{K^{ - 1}}

{27^0}C

then

\Delta G

will be

View answer and explanation

Correct option: C

–3.5 kJ

Option C (–3.5 kJ) is correct because it is calculated using the formula

\Delta G = \Delta U + \Delta(PV) - T\Delta S = \Delta U + \Delta nRT - T\Delta S

, where

\Delta n

is the change in the number of moles of gas.

Practice All Chapter MCQs →

{T_i}

{T_f}

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

\Delta G