JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

The tangent to the curve

y=x^3

at the point

P\left(t, t^3\right)

cuts the curve again at point

Q

. Then, the coordinates of

Q

are

View answer and explanation

Correct option: D

\left(-2 t,-8 t^3\right)

Option D ((-2t, -8t³)) is correct because it represents the other intersection point of the tangent line with the curve y=x³.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z