Skip to main content
Back to CHEMICAL KINETICS

NEET UG CHEMISTRY MCQ: CHEMICAL KINETICS

1 Hard
1 of 1
Application +4 | -1
For a fist order reaction, the concentration changes from 0.8  to  0.4  in  15  min.0.8\mathrm{ }\;to\;\mathrm{ }0.4\mathrm{ }\;in\mathrm{ }\;15\;\mathrm{ }min.. The time taken for the concentration to change from 0.1  M  to  0.025  M  is0.1\mathrm{ }\;M\;\mathrm{ }to\;\mathrm{ }0.025\mathrm{ }\;M\;\mathrm{ }is
View answer and explanation
Correct option: A
30 Min
Option A (30 Min) is correct because the time required for the concentration to halve is constant for a first-order reaction, and 0.1 M to 0.025 M represents two half-lives.

More Questions from CHEMICAL KINETICS

Practice All Chapter MCQs →
If the reaction rate at a given temperature becomes slower then 1[A]2\frac{1}{{{{\left[ A \right]}^2}}} vs times are a straight line. Order of reaction is The rate constant (k′)\left( {k'} \right) of one of the reaction is found to be double that of the rate constant (k′′)\left( {k''} \right) of another reaction. Then the relationship between the corresponding activation energies of the two reaction (E′a  and  E′′a)\left( {{{E'}_a}\;\mathrm{and}\;{{E''}_a}} \right) can be represented as Acid hydrolysis of sucrose is a Order of radioactive disintegration reaction is Temperature coefficient of a reaction is 2. When temperature is increased from 30∘C  to  100∘C30^\circ C\;to\;100^\circ C, rate of the reaction increases by
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →