JEE PHYSICS MCQ: OSCILLATIONS

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The amplitude of vibration of a particle is given by

{a_m} = ({a_0})/(a{\omega ^2} - b\omega + c);

where

{a_0},a,b

and c are positive. The condition for a single resonant frequency is

View answer and explanation

Correct option: A

{b^2} = 4ac

Option A (

{b^2} = 4ac

) is correct because for a single resonant frequency, the denominator of the amplitude equation must have only one real root, which occurs when the discriminant is zero.

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