Skip to main content
Back to SYSTEM OF CIRCLES

JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

1 Easy
1 of 1
Application +4 | -1
If S≡x2+y2+2x+3y+1=0S \equiv x^2+y^2+2 x+3 y+1=0 and S′≡x2+y2+4x+3y+2=0S^{\prime} \equiv x^2+y^2+4 x+3 y+2=0 are two circles, then the point (−3,−2)(-3,-2) lies
View answer and explanation
Correct option: A
inside S′S^{\prime} only
Option A (inside S′S^{\prime} only) is correct because substituting the point into the circle equations shows it's outside S and inside S'.

More Questions from SYSTEM OF CIRCLES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.