JEE PHYSICS MCQ: KINETIC THEORY OF GASES

1 Medium

1 of 1

Application +4 | -1

One mole of an ideal diatomic gas undergoes a process

P=\frac{P_0}{\left(1+\frac{V}{V_0}\right)^3}

, where

P_0

and

V_0

are positive constants. The translational kinetic energy of the gas when

V=V_0

is given by

View answer and explanation

Correct option: B

\frac{3 P_0 V_0}{16}

Option B (3 P₀ V₀ / 16) is correct because it is derived from the ideal gas law and the given process equation to find the translational kinetic energy.

More Questions from KINETIC THEORY OF GASES

Practice All Chapter MCQs →

Assertion: The pressure exerted by an enclosed ideal gas does not depend on the shape of the container.
Reason: The pressure of an ideal gas depends on the number moles, temperature and volume of the enclosed If

c_s

is the velocity of sound in air and

c

is the rms velocity, then Four particles have velocities

1,0,2,3 \mathrm{~m} / \mathrm{s}

. The root mean square of the particles is (in

\mathrm{m} / \mathrm{s}

) The translational degrees of freedom

(f_t)

and rotational degrees of freedom

(f_r)

{CH}_4

molecule are: On any planet, the presence of atmosphere implies (

{C_{rms}} =

= root mean square velocity of molecules and

{V_e} =

escape velocity) At a given temperature, the pressure of an ideal gas of density

\rho

is proportional to