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JEE MATHEMATICS MCQ: MEAN VALUES THEOREM

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If the function f(x)=x3−6  x2+ax+bf\left( x \right) = {x^3} - 6\;{x^2} + ax + b defined on [1,3], satisfies the Rolle’s theorem for c=23+13,c = \frac{{2\sqrt 3 + 1}}{{\sqrt 3 }},, then
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Correct option: C
a=11,b∈Ra = 11,b \in R
Option C (a=11,b∈Ra = 11,b \in R) is correct because Rolle's theorem requires f(1) = f(3), which leads to a = 11, and b can be any real number.

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