JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

If the tangent to the curve,

y = f\left( x \right) = x{\log _e}\,\,x,

(x > 0)

at a point

(c,\, f(c))

is parallel to the line segment joining the point (1, 0) and

(e, e)

then

c

is equal to

View answer and explanation

Correct option: B

{e^{\left( {\frac{1}{{e - 1}}} \right)}}

Option B (

{e^{\left( {\frac{{1}}{{e - 1}}} \right)}}

) is correct because it is the value of

c

that satisfies the condition of the tangent being parallel to the line segment.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z