The concentration of ${\rm{C}}{{\rm{O}}_2}$ be in equilibrium with $2.5 \times {10^{ - 2}}\;{\rm{mol}}\;{\rm{ litr}}{{\rm{e}}^{ - 1}}\;{\rm{of }}\;{\rm{CO}}\;{\rm{at}}\,\,100^\circ C$ for the reaction : ${\rm{FeO}}\left( s \right)\; + \,\,{\rm{CO}}\left( {\rm{g}} \right)\;\,\leftrightharpoons\;{\rm{Fe}}\left( s \right) + {\rm{C}}{{\rm{O}}_2}\left( {\rm{g}} \right);\;{K_c} = 5.0$

NEET UG CHEMISTRY MCQ: Equilibrium

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The concentration of

\mathrm{C}{\mathrm{O}_2}

be in equilibrium with

2.5 \times {10^{ - 2}}\;\mathrm{mol}\;\mathrm{ litr}{\mathrm{e}^{ - 1}}\;\mathrm{of }\;\mathrm{CO}\;\mathrm{at}\,\,100^\circ C

for the reaction :

\mathrm{FeO}\left( s \right)\; + \,\,\mathrm{CO}\left( \mathrm{g} \right)\;\,\leftrightharpoons\;\mathrm{Fe}\left( s \right) + \mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right);\;{K_c} = 5.0

View answer and explanation

Correct option: D

0125\;M

Option D (0.125 M) is correct because it is calculated using the equilibrium constant expression and the given concentration of CO.

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}