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NEET UG PHYSICS MCQ: ATOMS

1 Hard
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Analyzing +4 | -1
The radiation emitted when an electron jumps from 4th orbit to 2nd orbit in hydrogen like atom is made to incident on a metal surface to produce photoelectrons. In this way the ejected electrons are made to enter into a uniform magnetic field of strength 5 mT\sqrt{5} \,\mathrm{mT} and perpendicular to the direction of motion of the electrons. In the field electrons move on a circular path of radius 4.55 mm4.55 \mathrm{~mm}. If the work function of the metal is 1.1 eV1.1 \,\mathrm{eV}, then
(a) Atomic number of the atom.
(b) Stopping potential of the photoelectrons. Find a+b.a+b.
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Correct option: A
13
Option A (13) is correct because the atomic number and stopping potential can be calculated from the given information and their sum is 13.

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