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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1

Find the values of magnetic field between plates of capacitor at distance

1 \mathrm{~m}

from centre where electric field varies by

10^{10}

volt

/ \mathrm{m} / \mathrm{s}

.

View answer and explanation

Correct option: A

5.56 \times 10^{-8} \mathrm{~T}

Option A (

5.56 \times 10^{-8} \mathrm{~T}

) is correct because it is calculated using the formula for the magnetic field between the plates of a capacitor due to the changing electric field.

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