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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1

The charge of a parallel plate capacitor is varying as

q = {q_0}\sin 2\pi ft

. The plates are very large and close together (area

= A

, separation

= d

). Neglecting edge effects, the displacement current through the capacitor is

View answer and explanation

Correct option: C

2\pi f{q_0}\cos 2\pi ft

Option C (

2\pi f{q_0}\cos 2\pi ft

) is correct because the displacement current is the time derivative of the charge.

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