JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

\frac{{3 + 2i\sin \theta }}{{1 - 2i\sin \theta }}

will be purely imaginary, if

\theta

is equal to

View answer and explanation

Correct option: C

n\pi \pm \frac{\pi }{3}

Option C (

n\pi \pm \frac{\pi }{3}

) is correct because setting the real part of the expression to zero yields this general solution for

\theta

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