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JEE PHYSICS MCQ: THERMODYNAMICS

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One mole of helium is adiabatically expanded from its initial state (Pi,Vi,Ti)\left(P_i, V_i, T_i\right) to its final state (Pf,Vf,Tf)\left(P_f, V_f, T_f\right). The decrease in the internal energy associated with this expansion is equal to
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Correct option: A
CV(Ti−Tf){C}_{{V}}\left({T}_{{i}}-{T}_{{f}}\right)
Option A (CV(Ti−Tf){C}_{{V}}\left({T}_{{i}}-{T}_{{f}}\right)) is correct because the change in internal energy for an adiabatic process is given by ΔU=nCVΔT\Delta U = nC_V\Delta T, and in this case, the decrease is CV(Ti−Tf)C_V(T_i - T_f).

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