If $ f(x)=\frac{1-x}{1+x} $, the $ \mathrm{n} f[f(\cos 2 \theta)]= $

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

f(x)=\frac{1-x}{1+x}

, the

\mathrm{n} f[f(\cos 2 \theta)]=

View answer and explanation

Correct option: C

\cos 2 \theta

Option C (

\cos 2 \theta

) is correct because substituting

f(x)

into itself simplifies to

\cos 2 \theta

using trigonometric identities.

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}