NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

1 Hard

1 of 1

Application +4 | -1

Which one of the following will show paramagnetism corresponding to 2 unpaired electrons?
(Atomic numbers:

{Ni}=28, {Fe}=26

)

View answer and explanation

Correct option: B

\left[{NiCl}_4\right]^{2-}

Option B (

\left[{NiCl}_4\right]^{2-}

) is correct because it has a tetrahedral geometry with two unpaired electrons due to weak field ligand.

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\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

\text{ox =}

x

{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

\mathrm{M}{\mathrm{n}^{2 + }}

\mathrm{CuS}{\mathrm{O}_4}

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]