Question

A complex of cobalt has five ammonia molecules, one nitro group and two chlorine atoms for each cobalt atom. One mole of this compound produces three mole ions in aqueous solution which on treating with excess of ${\rm{AgN}}{{\rm{O}}_3}$ give two mole of ${\rm{AgCl}}$. The formula of the compound is:

Accepted Answer

$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}{\rm{N}}{{\rm{O}}_2}} \right]{\rm{C}}{{\rm{l}}_2}$

Answer

$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_4}{\rm{N}}{{\rm{O}}_2}{\rm{Cl}}} \right]\left[ {\left( {{\rm{N}}{{\rm{H}}_3}} \right){\rm{Cl}}} \right]$

Answer

$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}{\rm{Cl}}} \right]\left[ {{\rm{ClN}}{{\rm{O}}_2}} \right]$

Answer

$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}} \right]\left[ {{{\left( {{\rm{N}}{{\rm{O}}_2}} \right)}_2}{\rm{C}}{{\rm{l}}_2}} \right]$

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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