JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

The water of volume

4 \mathrm{~m}^3

at the height

20 \mathrm{~m}

is pressed by

2 \times 10^5 \mathrm{~N}

pressure. The work done by motor is

View answer and explanation

Correct option: B

16 \times 10^5 \mathrm{~J}

Option B (

16 \times 10^5 \mathrm{~J}

) is correct because the work done is the sum of the work done against gravity and the work done against pressure.

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\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)