JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Analyzing +4 | -1

Suppose

z \in \mathbf{C}

, and

z \notin \mathbf{R}

. If

w=\frac{1-z+z^2}{1+z+z^2}

is a real number, then

|z|

equals

View answer and explanation

Correct option: A

Option A (1) is correct because the condition that

w

is real implies that

z + \frac{{1}}{{z}}

is real, which leads to

|z| = 1

since

z

is not real.

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