JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

\omega=\cos \frac{\pi}{n}+i \sin \frac{\pi}{n}

, then value of

1+\omega+\omega^2+\ldots+\omega^{n-1}

View answer and explanation

Correct option: A

1+i \cot \left(\frac{\pi}{2 \pi}\right)

Option A (

1+i \cot (\frac{{\pi}}{{2 \pi}})

) is correct because it is derived from summing the geometric series and simplifying using trigonometric identities.

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