JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

f\left( 0 \right) = 1,f\left( 1 \right) = 5,f\left( 2 \right) = 11

then the equation of polynomial of degree two is

View answer and explanation

Correct option: B

{x^2} + 3x + 1 = 0

Option B (

{x^2} + 3x + 1 = 0

) is correct because it satisfies the given conditions f(0) = 1, f(1) = 5, and f(2) = 11.

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