NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

1 Medium

1 of 1

Application +4 | -1

An area of cross-section of rubber string is

2c{m^2}

. Its length is doubled when stretched with a linear force of

2 \times {10^5}dynes

. The Young’s modulus of the rubber in

dyne/c{m^2}

will be

View answer and explanation

Correct option: B

1 \times {10^5}

Option B (

1 \times {10^5}

) is correct because it is calculated using Young's modulus formula with the given force, area, and change in length.

More Questions from MECHANICAL PROPERTIES OF SOLIDS

Practice All Chapter MCQs →

1\,m{m^2}

N/{m^2}

\left[ {g = 10\,m{s^{ - 2}}\,} \right]\,

\mathrm{1 mm}

2\,\,m

1\,\,cm

0.8

Y

\mathrm{K}

\eta