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NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

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A 20 kg load is suspended by a wire of area of cross section is 1 mm21\,m{m^2}. The stress produced in N/m2N/{m^2} is [g=10 ms−2 ] \left[ {g = 10\,m{s^{ - 2}}\,} \right]\,
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Correct option: B
2×1082 \times {10^8}
Option B (2×1082 \times {10^8}) is correct because stress is calculated as force divided by area, where the force is the weight of the load (20 kg * 10 m/s²) and the area is 1 mm² converted to m².

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