JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

\frac{\sin ^2 3 A}{\sin ^2 A}-\frac{\cos ^2 3 A}{\cos ^2 A}=

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Correct option: B

8 \cos 2 A

Option B (

8 \cos 2 A

) is correct because the expression simplifies to

8 \cos(2A)

using trigonometric identities.

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