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JEE MATHEMATICS MCQ: MEAN VALUES THEOREM

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If f(x)f\left( x \right) satisfies the requirements of Rolle’s Theorem in [1,2]\left[ {\mathrm{1, 2}} \right] and f(x)f\left( x \right) is continuous in [1,2]\left[ {\mathrm{1, 2}} \right], then ∫12  f′(x)  dx\int \limits_1^2 \,\,f'\left( x \right)\,\,dx is equal to
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Correct option: A
0
Option A (0) is correct because Rolle's Theorem implies f(1) = f(2), and the integral of f'(x) from 1 to 2 is simply f(2) - f(1), which equals zero.

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