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JEE PHYSICS MCQ: GRAVITATION

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Application +4 | -1
The radius of the earth is 6.37×106 m6.37 \times 10^6 \mathrm{~m}, its mean density is 5.5×103 kg m−35.5 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3} and G=6.66×10−11 Nm2 kg−2G=6.66 \times 10^{-11}\mathrm{~Nm}^2 \mathrm{~kg}^{-2}. Determine the gravitational potential on the surface of the earth.
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Correct option: A
−6.22×107 J kg−1-6.22 \times 10^7 \mathrm{~J} \mathrm{~kg}^{-1}
Option A (21\frac{2}{1}) is correct because using the ideal gas law, the ratio of the number of gas molecules in A to B is 2:1.

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