JEE MATHEMATICS MCQ: MAXIMA & MINIMA

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Analyzing +4 | -1

The least distance of the point

Q(0,-2)

from the point

P(x, y)

where

y=\frac{16}{\sqrt{3} x^3}-2

and

x>0

View answer and explanation

Correct option: C

4 / \sqrt{3}

Option C (

4 / \sqrt{3}

) is correct because it is the minimum distance calculated by finding the critical point of the distance function and verifying it's a minimum.

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m(b)

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b

m(b)

f: R \rightarrow R

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p

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\left[ {1/\sqrt 3 ,\;\sqrt 3 } \right]

f(x)=\left(\frac{\sqrt{3 e}}{2 \sin x}\right)^{\sin ^{2} x}, x \in\left(0, \frac{\pi}{2}\right),

\frac{k}{e}

\left(\frac{k}{e}\right)^{8}+\frac{k^{8}}{e^{5}}+k^{8}