In a $\Delta \,ABC$ if $a = 26,\,\,b = 30$ and $\cos \,\,C = \frac{{63}}{{65}}$, then ${r_2} = $

JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

In a

\Delta \,ABC

a = 26,\,\,b = 30

and

\cos \,\,C = \frac{{63}}{{65}}

, then

{r_2} =

View answer and explanation

Correct option: C

\mathrm{48}

Option C (48) is correct because by using the cosine rule to find c and then using Heron's formula to find the area,

r_2

can be calculated as

\frac{\Delta}{s-b}

Practice All Chapter MCQs →

{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s