JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

The vector

z = - 4 + 5\;i

is turned counterclockwise through an angle of

180^\circ

and stretched

1\frac{1}{2}

times. The complex number corresponding to newly obtained vector is

View answer and explanation

Correct option: A

6 - \frac{{15}}{2}i

Option A (

6 - \frac{{15}}{2}i

) is correct because it is the result of rotating the vector counterclockwise by 180 degrees and stretching it by a factor of 1.5.

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{\left| {1 - i} \right|^x} = {2^x}

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z \neq \pm 1

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\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

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