If $\sin A + \cos A = m$ and ${\sin ^3}A + {\cos ^3}A = n$, then

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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\sin A + \cos A = m

and

{\sin ^3}A + {\cos ^3}A = n

, then

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Correct option: C

{m^3} - 3m + 2n = 0

Option C (

{m^3} - 3m + 2n = 0

) is correct because it represents the relationship derived by cubing the first equation and substituting the second equation.

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