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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1
Let z=cos⁡θ+isin⁡θz=\cos \theta+i \sin \theta. Then the value of ∑m=115Im⁡(z2m−1)\sum\limits_{{m=1}}^{15} \operatorname{Im}\left(z^{2 m-1}\right) at θ=2∘\theta=2^{\circ} is
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Correct option: D
14sin⁡2∘\frac{1}{4 \sin 2^{\circ}}
Option D (14sin⁡2∘\frac{1}{4 \sin 2^{\circ}}) is correct because by using the formula for the sum of a geometric series and trigonometric identities, the given sum simplifies to 14sin⁡2∘\frac{1}{4 \sin 2^{\circ}}.

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