JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

The domain of the definition of the function

f\left( x \right) = \sqrt {1 + {{\log }_e}\left( {1 - x} \right)}

View answer and explanation

Correct option: B

- \infty < x \le \frac{{e - 1}}{e}

Option B (

- \infty < x \le \frac{{e - 1}}{e}

) is correct because it represents the domain where the function is defined, considering the logarithm and square root.

More Questions from FUNCTIONS

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S=\left\{x: f(x)=f^{-1}(x)\right\}