Question

Two light rays having the same wavelength $\lambda $ in vacuum are in phase initially. Then the first ray travels a path ${{L_1}}$ through a medium of refractive index ${{n_1}}$ while the second ray travels a path of length ${{L_2}}$ through a medium of refractive index ${{n_2}}$. The two waves are then combined to produce interference. The two waves are then combined to produce interference. The phase difference between the two waves is

Accepted Answer

$\frac{{2\pi }}{\lambda }\left( {{n_1}{L_1} - {n_2}{L_2}} \right)$

Answer

$\frac{{2\pi }}{\lambda }\left( {{L_2} - {L_1}} \right)$

Answer

$\frac{{2\pi }}{\lambda }\left( {{n_2}{L_1} - {n_1}{L_2}} \right)$

Answer

$\frac{{2\pi }}{\lambda }\left( {\frac{{{L_1} - {L_2}}}{{{n_1} - {n_2}}}} \right)$

NEET UG PHYSICS MCQ: WAVE OPTICS

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