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NEET UG PHYSICS MCQ: WAVE OPTICS

1 Hard
1 of 1
Application +4 | -1
Two coherent sources emit light waves, which superimpose at a point where these can be expressed as

E1=E0sin⁡(ωt+π/4)E2=2E0sin⁡(ωt−π/4)\begin{aligned} & \mathrm{E}_1=\mathrm{E}_0 \sin (\omega \mathrm{t}+\pi / 4) \\ & \mathrm{E}_2=2 \mathrm{E}_0 \sin (\omega \mathrm{t}-\pi / 4) \end{aligned}

here E1\mathrm{E}_1 and E2\mathrm{E}_2 are the electric field strengths of the two waves at the given point. If I\mathrm{I} is the intensity of wave expressed by field strength E1\mathrm{E}_1, find the resultant intensity.
View answer and explanation
Correct option: D
5I5 \mathrm{I}
Option D (5I5 \mathrm{I}) is correct because the resultant intensity is calculated by considering the phase difference and amplitudes of the two interfering waves.

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