JEE MATHEMATICS MCQ: STRAIGHT LINES

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Application +4 | -1

The equations of the lines through

(-1,-1)

and making angle

45^{\circ}

with the line

x+y=0

are given by

View answer and explanation

Correct option: D

xy + x + y + 1 = 0

Option D is correct. The combined equation of the lines through (-1,-1) and making an angle of 45 degrees with x+y=0 is found to be

xy + x + y + 1 = 0

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\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

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x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0