JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Analyzing +4 | -1

Two particles of equal masses have velocities

{v}_1=4 \hat{i}{\mathrm{~ms}}^{-1}

and

{v}_2=4 \hat{{j}} \mathrm{~ms}^{-1}.

First particle has an acceleration

a_1=(2 \hat{i}+2 \hat{j}) \mathrm{ms}^{-2},

while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of:

View answer and explanation

Correct option: A

straight line

Option A (straight line) is correct because the center of mass has a constant acceleration parallel to its velocity, resulting in linear motion.

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