JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Analyzing +4 | -1

\int \frac{x^2 \cos x}{(1+\sin x)^2} d x= \frac{-x^2}{1+\sin x}-2 x(\sec x-\tan x)+2 \log |f(x)|+c

where

f(x)

is equal to

View answer and explanation

Correct option: C

1+\sin x

Option C (

1+\sin x

) is correct because, after integration by parts and simplification, the logarithmic term involves

1+\sin x

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