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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
1 of 1
Application +4 | -1
Let an=i(n+1)2{a_n} = {i^{{{\left( {n + 1} \right)}^2}}}, where i=−1i = \sqrt { - 1} and n=1,  2,  3,…n = 1,\;2,\;3, \ldots Then the value of a1+a3+a5+...+a25{a_1} + {a_3} + {a_5} + ... + {a_{25}} is
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Correct option: A
13
The correct answer is A (13) because the series a1+a3+a5+...+a25{a_1} + {a_3} + {a_5} + ... + {a_{25}} simplifies to a sum of 13 ones.

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