JEE PHYSICS MCQ: THERMODYNAMICS

1 Medium

1 of 1

Application +4 | -1

0^{\circ} \mathrm{C}

and normal atmospheric pressure, the volume of

1 \mathrm{~g}

of water increases from

1 \mathrm{~cm}^3

1.091 \mathrm{~cm}^3

on freezing. What will be the change in its internal energy? Normal atmospheric pressure is

1.013 \times 10^5 \mathrm{~Nm}^{-2}

and latent heat of melting of ice

=80 \mathrm{~cal} \mathrm{~g}^{-1}

View answer and explanation

Correct option: A

-80.0022 \mathrm{~cal}

Option A (

-80.0022 \mathrm{~cal}

) is correct because it accounts for both the heat lost during freezing and the work done against atmospheric pressure.

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