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JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

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Understanding +4 | -1

Consider a capacitor - charging circuit. Let

Q_1

be the charge given to the capacitor in time interval of

20 \mathrm{~ms}

and

Q_2

be the charge given in the next time interval of

20 \mathrm{~ms}

. Let

10 \mu \mathrm{Ccharge}

be deposited in a time interval

t_1

and the next

10 \mu \mathrm{C~charge}

is deposited in the next time interval

t_2

. Then,

View answer and explanation

Correct option: B

Q_1 > Q_2, t_1 < t_2

The correct answer is B (Q1 > Q2, t1 < t2) because as the capacitor charges, the charging rate decreases, meaning more charge is deposited initially and it takes longer to deposit the same amount of charge later.

More Questions from ELECTRIC POTENTIAL AND CAPACITANCE

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The potential at a point distance

x

(measured in

\mu \mathrm{m}

) due to some charges situated on the

x

axis is given by

V(x)=\frac{20}{x^2-5} \mathrm{V}

. The electric field at

x=5 \mu \mathrm{m}

is given by: A parallel plate capacitor is connected to a 5V battery and charged. The battery is then disconnected and a glass slab is introduced between the plates. Then, the quantities that decrease are A conducting sphere of radius

R

is given a charge

Q

. The electric potential and the electric field at the centre of the sphere respectively are Two capacitors when connected in series have a capacitance of

3\mu F,\,

and when connected in parallel have a capacitance of

16\mu F

. Their individual capacities are Statement-1: If temperature is increased, the dielectric constant of a polar dielectric decreases whereas that of a non-polar dielectric does not change significantly.
Statement-2: The magniude of dipole moment of individual polar molecule decreases significantly with increase in temperature. An electric dipole when placed in a uniform electric field

E

will have minimum potential energy, if the positive direction of dipole moment makes the following angle with

E