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JEE MATHEMATICS MCQ: MAXIMA & MINIMA

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Application +4 | -1
The curve y(x)=ax3+bx2+cx+5y(x)=a x^3+b x^2+c x+5 touches the xx-axis at the point P(−2,0)P(-2,0) and cuts the yy-axis at the point QQ, where y′y^{\prime} is equal to 3 . Then the local maximum value of y(x)y(x) is
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Correct option: A
274\frac{27}{4}
Option C (33228\frac{{33}}{{2^{28}}}) is correct because it represents the probability of one or two successes, calculated using the binomial distribution formula and the given mean and variance.

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